(x^2+4)dy=(2x-8xy)Dx

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Solution for (x^2+4)dy=(2x-8xy)Dx equation: 


Simplifying
(x2 + 4) * dy = (2x + -8xy) * Dx

Reorder the terms:
(4 + x2) * dy = (2x + -8xy) * Dx

Reorder the terms for easier multiplication:
dy(4 + x2) = (2x + -8xy) * Dx
(4 * dy + x2 * dy) = (2x + -8xy) * Dx

Reorder the terms:
(dx2y + 4dy) = (2x + -8xy) * Dx
(dx2y + 4dy) = (2x + -8xy) * Dx

Reorder the terms for easier multiplication:
dx2y + 4dy = xD(2x + -8xy)
dx2y + 4dy = (2x * xD + -8xy * xD)
dx2y + 4dy = (2x2D + -8x2yD)

Solving
dx2y + 4dy = 2x2D + -8x2yD

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Reorder the terms:
dx2y + 4dy + -2x2D + 8x2yD = 2x2D + -2x2D + -8x2yD + 8x2yD

Combine like terms: 2x2D + -2x2D = 0
dx2y + 4dy + -2x2D + 8x2yD = 0 + -8x2yD + 8x2yD
dx2y + 4dy + -2x2D + 8x2yD = -8x2yD + 8x2yD

Combine like terms: -8x2yD + 8x2yD = 0
dx2y + 4dy + -2x2D + 8x2yD = 0

The solution to this equation could not be determined.

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